Simple Tower Of Hanoi Algorithm in Python

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The objective of the Tower of Hanoi mathematical game or puzzle is to move the entire stack to another rod, the following simple rules should be obeyed:

  1. Only 1 disk can be moved at a time.
  2. In Each move you can take the upper disk from one of the stacks and place it on top of another stack.
  3. No disk can be placed on top of a smaller disk
tower of Hanoi algorithm in Python

Python Program for Tower of Hanoi :

# source rod A = [] # middle rod B = [] # target rod C = [] def showAll():    print(A, B, C, '_________________', sep = '\n'); def move(n, source, target, bridge): if n > 0: # move n - 1 disks from source to bridge, so they are out of the way move(n - 1, source, bridge, target) # move the nth disk from source to target target.append(source.pop()) # Display our progress showAll() # move the n - 1 disks that we left on bridge onto target move(n - 1, bridge, target, source) discs = int(input("Number of disks: ")) print(discs, '_________________', sep = '\n'); A = list(range(1, discs+1))[::-1] showAll() # initiate call from source A to target C with auxiliary B move(discs, A, C, B) print("Number of moves:" + str(2**discs - 1))

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