Algorithm and Flowchart for Armstrong Number

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What is an Armstrong number?

An Integer number in which the sum of the cubes of its digits is equal to the number itself is called Armstrong Number. For example, 153 is an Armstrong number since 1**3 + 5**3 + 3**3 = 153.
(NOTE: 5**3 is nothing but 5*5*5)

Pseudocode and Algorithm for Armstrong Number

Algorithm to find whether number is Armstrong Number or Not

Step 1: Start Step 2: Declare Variable sum, temp, num Step 3: Read num from User Step 4: Initialize Variable sum=0 and temp=num Step 5: Repeat Until num>=0 5.1 sum=sum + cube of last digit i.e [(num%10)*(num%10)*(num%10)] 5.2 num=num/10 Step 6: IF sum==temp Print "Armstrong Number" ELSE Print "Not Armstrong Number" Step 7: Stop

Pseudocode to find whether number is Armstrong Number or Not:

READ n temp=n sum=0 WHILE n>=0 sum=sum+(n%10)*(n%10)*(n%10) n=n/10 ENDWHILE IF sum==temp WRITE "NUMBER IS AN ARMSTRONG NUMBER" ELSE WRITE "NUMBER IS NOT AN ARMSTRONG NUMBER"

We first take input from user and store it in variable n. Then we initialize 2 variables temp to n and sum to 0. We calculate the cube of last digit by this expression [(n%10)*(n%10)*(n%10)] and add it to value of sum and also divide n by 10. We repeat the above step until n is greater than or equal to 0. At last, we check whether sum is equal to temp, if yes Print "Number is Armstrong Number" else print "Number is Not Armstrong Number".

Flowchart For Armstrong Number

Flowchart for Armstrong Number
Remove WaterMark from Above Flowchart
Armstrong Number Implementation in Python: Python Program to Check Armstrong number

                 

Updated on 7 MARCH, 2021 by Shaddy


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Comments

7 comment
  • Saikrisgna

    Thanks for giving valuable information
  • sam joshua

    You are doing great and website is not fancy like programiz
  • Rithwik

    Thank you for above algorithm It was really useful
  • James

    Thank you for the Notes. Was very useful.
  • aravindkumar

    bro thanking for your post
  • trunks

    Excellent. Just a note in the loop of while the condition should be "while (num>0)" cause' of add the "=" it doesn't work. Thank you
  • Shaddy

    @trunks, while (num>=0) works properly. I tried it myself


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